Calculate the energy, in Joules, of a photon of red light that has a frequency of 4.35 x (10)14s-1?

Question

a) 6.90 x 10(-7)
b) 2.88 x 10(-19)
c) 4.35 x 10(14)
d) 1.45 x 10(-10)
e) 1.04 x 10(27)

Answer 1

The equation you need is

f λ = c

where f is the frequency, λ the wavelength, and c the speed of light. You are given two of these quantities; plug 'em in and solve for the third.

Answer 2

For multiplying fractions, in basic terms multiply the coolest numbers and the backside numbers. So (2 * a million)/(5 * 10) = 2 / 50. in spite of the undeniable fact that, the two the coolest and the backside of the fraction 2 / 50 may well be divided with the help of two to simplify the fraction to a million / 25. including fractions is greater problematical. First discover the liquid crystal reveal of 15 and 5 (the smallest quantity that 15 and 5 bypass into). 15 is the smallest quantity that is divided with the help of 15 and 5, so it somewhat is the liquid crystal reveal. The liquid crystal reveal, that's 15, is the quantity which you somewhat desire to alter the two fractions to have a denominator of. the 1st quantity, 13/15, already has a denominator of 15, so go away it on my own for now. the 2d quantity, 2/5, could be expanded (the two the coolest and the backside) with the help of three to get a denominator of 15. this provides us 6/15. Then calculate 13/15 - 6/15 with the help of in basic terms subtracting the coolest of the fractions (that's in basic terms legal if the bottoms are a similar). So 13/15 - 6/15 = 7/15. 7/15 can't be simplified.

Answer 3

Photonic energy is E = hf; whre h is Planck's constant and f = 4.35 X 10^14 cycles/sec. h = 6.626 × 10^-34 joule-seconds where a Joule = kg (m/sec)^2.

By eyeball, we can see b) is correct because it has the correct order of magnitude.