English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

How far (in terms of A) is this mass from the equilibrium position of the spring when the elastic potential energy equals the kinetic energy?

2007-12-02 05:20:30 · 2 answers · asked by SweetMandy01234 2 in Science & Mathematics Physics

I understand your answer but i am struggling with the algebra aspect of this problem. I had the same thing but i can not get the correct answer for whatever reason

2007-12-02 05:36:48 · update #1

2 answers

The total energy of the system when the spring when fully extended is

1/2 k A^2

You want to know the displacement where potential energy = kinetic energy. Another way to say that is, you want the position where the potential energy is half of the maximum. In other words, you want to solve

1/2 k x^2 = ( 1/2 ) 1/2 k A^2

for x. The answer will be in terms of A, as desired.

2007-12-02 05:26:03 · answer #1 · answered by jgoulden 7 · 2 4

d = .707

2015-04-19 15:28:42 · answer #2 · answered by Jarrett 2 · 4 0

fedest.com, questions and answers