Geometry Help?

Question

Angle MOE is bisected by ray OP. Angle MOP =10-3x and Angle POE = X^2-6X. What does angle MOE equal using the qudratic formula or factoring.

I couldn't come up with a reasonable answer using either method to solve it. Can someone help me?

Answer 1

ok since ray OP bisects the ange MOE it splits the angle directly in half. thus resulting the equation
10-3x = x^2 -6x
x^2 - 3x -10 = 0
(x-5)(x+2)=0
x=5,-2

Answer 2

Since OP is the bisector of MOE


x^2 - 6x = 10 - 3x

x^2 - 3x - 10 = 0

(x -5)(x + 2) = 0

x = 5 or -2

x = -2 is a valid one since if x = 5 , then the angles will be negative.

substituting x = -2 in 10 -3x


so MOE = 2(16) = 32 degrees

Answer 3

Given OP bisect so, i.e.,10-3x=x²-6x
or x²-3x-10=0
(x-5)(x+2)=0
x=5,-2

But =10-3x+x²-6x
=x²-9x+10

So,if x=5,
=-10
Thats impossible(as angle won't be given as negative here)

So,x=-2
So, =32

Answer 4

10-3x= x^2-6x
x^2-3x-10=0 x= ((3+-7))/2 = 5 so MOE = 10 ( don´t know the units)