x^2-2x-15=0
2007-12-02 04:26:20 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x - 5) (x + 3) = 0
x = 5 , x = - 3
2007-12-02 10:37:57 · answer #1 · answered by Como 7 · 2⤊ 1⤋
x^2-2x-15=0
Factor:
(x-5)(x+3)
Set equal to zero:
x-5=0 x+3=0
x=5 or x= -3
2007-12-02 04:38:08 · answer #2 · answered by Anonymous · 0⤊ 1⤋
x^2-2x-15=0
Factor:
(x+3)(x-5)=0
Set each factor equal to zero:
x+3= 0
x-5=0
Solve:
x= -3, 5
2007-12-02 04:28:23 · answer #3 · answered by victoria 5 · 1⤊ 0⤋
write the equation as: x^2 -5x +3x -15 = 0
--> x(x-5) + 3 (x-5) = 0
take x-5 as common
this gives,
--> (x+3)(x-5) = 0
--> x= 5,-3
2007-12-02 04:29:39 · answer #4 · answered by The learner 2 · 1⤊ 1⤋
(x-5)(x+3) = 0
x = 5, -3
2007-12-02 04:29:11 · answer #5 · answered by RobertJ 4 · 1⤊ 0⤋
NO SOLUTION.
2007-12-02 04:34:13 · answer #6 · answered by Mahøgany 4 · 0⤊ 1⤋