lim x^2+3x-5
x--->2
lim 2x+5/x-3
x--->3
lim x^2-x-6/x-3
x--->3
2007-12-02 03:46:47 · 3 answers · asked by 3Sigma 1 in Science & Mathematics ➔ Mathematics
1) This limit can be done by plugging in 2 as x.
(2)^2+3(2)-5 = 4+6-5=5
2) This one is undefined so find the limit using the derivatives of the numerator and denominator
2/1 = 2
3) Same thing as above
(2x-1)/1 = 2(2)-1 = 3
2007-12-02 03:52:51 · answer #1 · answered by someone2841 3 · 0⤊ 0⤋
You're leaving out some parentheses...
1. lim x->2 x^2 + 3x - 5 = 4 + 6 - 5 =5
2. lim x->3 (2x + 5)/(x - 3) = undefine
3. lim x->3 (x^2 - x - 6)/(x - 3) = lim x->3 x+2 = 3 + 2 = 5
2007-12-02 03:51:00 · answer #2 · answered by UnknownD 6 · 0⤊ 0⤋
Just replace x by the value that it tends to in the function.
2007-12-02 03:50:54 · answer #3 · answered by Madhukar 7 · 0⤊ 0⤋