2007-12-01 18:25:02 · 6 answers · asked by tobi 1 in Science & Mathematics ➔ Mathematics
Assuming that these are horizontal forces:-
R = 100 - 160 N
R = - 60 N
ie 60 N TO THE LEFT
2007-12-01 22:45:06 · answer #1 · answered by Como 7 · 4⤊ 0⤋
total right force... 40+60=100
left force...160
the difference is 60 N to the left
2007-12-01 18:29:38 · answer #2 · answered by Allen C 3 · 0⤊ 0⤋
you're able to sum up the magnitudes, taking the guidelines under consideration. on account that that's a one-dimensional case, that's exceedingly easy, we are going to take forces to the main appropriate as helpful and ones to the left as unfavorable and sum them up: F = F1 + F2 + F3 = ( +40 ) + ( +60 ) + ( -a hundred and sixty ) = one hundred - a hundred and sixty = -60 the internet rigidity is 60 N to the left.
2016-11-13 05:50:15 · answer #3 · answered by ? 4 · 0⤊ 0⤋
60. (160-40-60=60)
2007-12-01 18:30:17 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Hello is my answer haha i just want to get points ill suck for 30 points and a FCK for a 50 points
2007-12-01 18:47:39 · answer #5 · answered by Anonymous · 0⤊ 1⤋
the above answers are right as long as they are at the same distance from the equillibrium. but if not, the distance does matter.
2007-12-01 18:36:05 · answer #6 · answered by Lyon 2 · 0⤊ 0⤋