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She asked me and my cousin and she said whoever will get the right answer will get 10 Bucks.
Here are the questions:
1. Is it possible for two colorblind parents to have a normal vision son? (If yes, show proof with a punnett square.)
This kind of exercise was from my softmore year now I'm a senior and I forgot it.
Please guys help me win the money.
Thanks in advance!!!

2007-12-01 16:34:08 · 5 answers · asked by Anonymous in Science & Mathematics Biology

5 answers

it depends if the colorblindness is recessive or dominant
it its dominant, then its possible because
lets call colorblindness 'B' and normal 'b'
you can have the possibility of
Bb x Bb cross of two color blind parents
the results can be the following
BB, bb, and Bb
if u happen to be the bb then ur not color blind

if its recessive then both parents must have that trait in both alleles, in otherwords both must be bb since thats the only way they can have the allele be expressed, so then you canot obtain a normal son.

2007-12-01 16:41:46 · answer #1 · answered by Zmik 3 · 1 1

It's simple: IFmom is colorblind, ALL her sons will be colorblind also. Dad's genetic make-up doesn't matter in this case!

Colorblindness is a sex-linked trait.
By the way, a colorblind female is relatively rare.

2007-12-02 02:04:32 · answer #2 · answered by ursaitaliano70 7 · 1 0

Yes, I think it is. The child's grandparents may have the gene for good vision. If both parents had parents who carried that gene maybe colorblindness by misfortune was the trait they received. However, when the child received the carrier gene for colorblindness if he is luckier he won't receive the colorblindness.

2007-12-02 00:44:06 · answer #3 · answered by Anonymous · 1 0

If it's red-green colorblind and there's no mutation in the son, then.....no. He'll be colorblind.

2007-12-02 00:42:31 · answer #4 · answered by Anonymous · 0 0

its kinda hard to draw a square here...

I am pretty sure its the MALE line that passes on color blindness...

2007-12-02 00:42:13 · answer #5 · answered by CF_ 7 · 0 0

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