This is pre algebra solving in quadratic method. please help thank you
2007-12-01 15:34:24 · 6 answers · asked by lsilva1980 1 in Science & Mathematics ➔ Mathematics
(x-3)^2 = 81 . Take the square root of both sides
x-3 = 9 or x-3 = -9
Solve both equations
x = 12 or x = -6
2007-12-01 15:40:51 · answer #1 · answered by Ralph G 2 · 1⤊ 0⤋
(x-3)squared =81 becomes
x^2-6x+9=81
x^2-6x-72=0
factors to (x-12)(x+6)=0
if you want to use the quadratic formula,
a=1, b=-6, c=-72
2007-12-01 23:41:27 · answer #2 · answered by Paladin 7 · 0⤊ 0⤋
(x-3)^2=81
(x-3) = 9 (square root both sides)
x=12 (add 3 to both sides)
2007-12-01 23:43:40 · answer #3 · answered by erin j 2 · 0⤊ 1⤋
x - 3 = ± 9
x = 12 , x = - 6
2007-12-05 11:10:29 · answer #4 · answered by Como 7 · 2⤊ 0⤋
(x-3)^2 = 81
Take the square root of both sides to get:
(x-3) = 9
Add three to both sides to get:
x = 12
2007-12-01 23:37:59 · answer #5 · answered by thingstealer 2 · 0⤊ 1⤋
(x-3)² = 81
x - 3 = ± 9
x' => x' - 3 = 9 => x' = 12
x" => x" - 3 = - 9 => x" = - 6
2007-12-01 23:48:14 · answer #6 · answered by piano 7 · 0⤊ 0⤋