how do i solve this chemistry gas problem?

Question

how do i solve this problem?

a sample of gas occupies 2.50 liters at 1.15 atm of pressure. what is its volume in standard atmospheric pressure?

p.s.if we are finding volume then why does it need to be in standard atmospheric PRESSURE?

Answer 1

This is Boyle's Law. Inverse proportion at constant temperature. P1 x V1 = P2 x V2.

P1 x V1 = P2 x V2
1.15atm x 2.5L = 1atm x V2
V2 = (1.15 x 2.5) ÷ 1 = 2.875L

Pressure Decrease <====> Volume Increase.

Answer 2

The volume of a gas depends on the temperature and the pressure as the pressure drops the volume will expand. Temperature here is not changing, so we can use:

P1V1 = P2V2 thus:

V1 x (P1/P2) = V2;

2.50L x (1.15/1.00) =

2.875L

Answer 3

divide the number of liters by the pressure in atm and you get 2.04 liters at standard atmospheric pressure. The gas is at a different pressure, and you need to find out what it would be at standard pressure.

Answer 4

a million First discover the style of moles of each gas modern-day. Moles CH4 = 2.5 grams over 16 grams in line with mole = .156 moles Moles N2 = 2.5 grams over 28 grams in line with mole = .089 moles Moles NH3 = 2.5 grams over 17 grams in line with mole = .147 moles finished moles = .539 Partial pressures of each gas in a mixture of gases is immediately percentage to the mole fraction of that gas. Mole fraction CH4 = .156 moles over .539 moles finished = .289 answer to 1c Partial rigidity NH3 .147 moles over .539 finished moles = .273 moles fraction NH3 i will end the following and calculate the completed rigidity PV = nRT P = nRT over V P in atmospheres = ( .539 moles finished)( circumstances gas consistent R (.082) circumstances kelvin temp of 288 ranges over a million.5 Liters volume 8.40 9 atmospheres finished rigidity in flask. answer for a million b now for partial rigidity of NH3. 8.40 9 atm finished rigidity circumstances .273 mole fraction NH3 = 2.32 atm. 2 a No including gas C does no longer impression the partial rigidity of A. each and each gas promises its autonomous partial rigidity. b. definite, including gas C will advance the completed rigidity contained in the vessel c. definite, including yet another gas to the sequence reduces each and each gas mole fraction.