For y = Sin(x), there is no circle with origin (0,0) that can be tangent to the Sin(x) function anywhere locally. For a certain k and greater, a circle with origin (0,0) can be tangent to the Sin(kx) function. What is the minimum value k for which such a circle exists, and what is the diameter of the circle?
2007-12-01
14:26:35
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2 answers
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asked by
Scythian1950
7
in
Science & Mathematics
➔ Mathematics
The circle with the embedded tangent Sin(kx) looks like the Yin-Yang symbol, without the dots.
2007-12-01
14:28:31 ·
update #1
Yeah, that's right folks, ksoileau nailed this one. Right down to 5th place accuracy. What was his method of numerical approximation?
2007-12-02
01:16:14 ·
update #2