English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1.018 g of a Freon gas is trapped in a 145 mL container at 760 mmHg and 50.0 ^C

2007-12-01 14:17:04 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Just use the ideal gas law, solving for n (moles), make certian everything is in the proper units! Then use the mass to find out what a whole mole would weigh.

PV = nRT, n = PV/RT

n = 1atm x 0.145L/0.08206Latm/moleK x 323K

n = 0.00547

1.018g/0.00547mole = 186g/mole

2007-12-01 14:30:44 · answer #1 · answered by Flying Dragon 7 · 0 0

First, you have to find the number of moles in freon gas. You can find this by using:

PV = nRT

where P is pressure (atm), V is volume (liters), n is moles, R is a constant (0.0821), and T is temperature(kelvin).

760 mmHg = 1 atm
145 mL = 0.145 L
50.0^C = 323 K
solve for n

1(0.145) = n(0.0821)(323)
0.145 = n (26.5183)
n = 0.0054679222

n is the number of moles.

so, to find the molar mass.

molar mass = mass/moles

1.018/0.0054679222 = 186.18

so molar mass of Freon = 186.18 g/mol

I hope that helps. I'm pretty sure that's right. Hopefully I didn't do anything wrong.

2007-12-01 22:37:43 · answer #2 · answered by thatonegirl 2 · 0 0

fedest.com, questions and answers