URGENTTT..which one?

Question

A 59.7 kg, 3.4 m uniform ladder leans against a frictionless wall. A 90.7 kg person is standing up 0.74 m from the bottom of the ladder. The ladder makes an angle of 63 degrees with the horizontal. The coefficient of static friction between the ladder and the ground is 0.15. What is the force of the wall on the top of the ladder?

A. 221.1 N
B. 841.9 N
C. 25.3 N
D. 396.7 N
E. 247.6 N

Answer 1

Let's find the forces first assuming the ladder doesn't slip
The force on the wall is purely horizontal since the wall is frictionless
call it F
Summing torques at the bottom of the ladder

g*cos(63)*(90.7*0.74+59.7*3.4/2)-
F*sin(63)*3.4=0

solve for F, g=9.8

F=247.6 N

This is a purely horizontal force, to see if the ladder slips see if the Normal component of the reaction force*0.15 is greater than 247.6
The normal force is the sum of
9.8*(90.7+59.7)
1474 N
the force of friction is 221, so the ladder slips.

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