polar coordinates?

Question

Given the point (5.7, -1.2) in rectangular coordinates, find its polar coordinates.

please help & explain step by step so I can follow, thanks

Answer 1

r = sqrt(5.7^2+-1.2^2) = 5.8

theta = arctan(y/x) = arctan ((-1.2/5.7) = -11.89 or 348.11

(5.8, -11.89)

Answer 2

Draw a coordinate plane, and plot the point. Use the distance formula to find the point's distance from the origin. Then draw in sides to create a right triangle between the point, the x-axis, and the origin, with the length between the point and the origin as the hypotenuse. The legs of the triangle should be the coordinates of the point. Make sure to keep the negative value of the y-coordinate. Use the inverse tangent to find the angle in radians on your calculator. The final coordinates are composed of the distance from the origin d and the angle, theta: (d, theta)

Answer 3

First, draw out the oblong coordinates, and also you'll have 2 aspects to a triangle. The third side is going from the muse to the point that the oblong coordinates specifiy. Then, basically use trigonometry (SOHCAHTOA) to discover the attitude and the dimensions of the hypotenuse. those 2 issues are used to provide the "polar coordinates" of that similar element. In different words, this is only a diverse thanks to get to a similar element. one way--oblong coordinates--you're instructed how some distance to bypass left and how some distance up. (or properly and down, yet you get the perception). any opposite direction--polar coordinates--you tell what number ranges to rotate, then how some distance to bypass in that route.

Answer 4

x= 5.7
y = -1.2
theta = arctan(-1.2/5.7)
r = sqrt(5.7^2 + 1.2^2)

if you want to physically see it draw the triangle. make the third point be the origin, you'll find out that the hypotenuse is r and the angle that r makes with the x axis is theta.

Answer 5

to convert from rect (x,y) co-ord to polar (r, a) use the formula

r^2 = x^2 + y^2
a = arctan(y/x)

the rest is using the calculator.