The bearing form B to C is S41W. From point A, 200 yards from B, the bearings to B and C are S74E and S28E respectively.
Find the distance from B to C.
What's confusing is that how can B and C have two bearings that is SE?
2007-12-01 11:14:23 · 1 answers · asked by hiddengirl 1 in Science & Mathematics ➔ Mathematics
The reason why you are confused is that you don't understand the use of the term "respectively". If I say Dick and Jane had apple pie and blueberry pie respectively, I mean Dick had apple pie and Jane had blueberry pie. First goes with first, second goes with second.
Here they are saying that the bearing from point A to point B is S74E, and the bearing from point A to point C is S28E.
Look at the sketch:
http://s236.photobucket.com/albums/ff177/jsardi56/?action=view¤t=bearings12-1-07.jpg
By alternate interior angles we have:
angle C = 28 + 41 = 69degrees
We need to find BC. Use the law of sines:
a/sinA = c/sinC
BC/sin(74 - 28) = 200/sin69
BC = 200sin46/sin69
BC = 154.10yds
2007-12-01 15:33:24 · answer #1 · answered by jsardi56 7 · 0⤊ 0⤋