x^2/5 divide by x^7/5
2007-12-01 10:57:46 · 10 answers · asked by Rhonda H 1 in Science & Mathematics ➔ Mathematics
2/7
2007-12-01 11:00:56 · answer #1 · answered by Anonymous · 0⤊ 1⤋
x ^(2/5 - 7/5) = x ^ -1 = 1/x
2007-12-01 11:02:31 · answer #2 · answered by jamesyoy02 6 · 0⤊ 1⤋
The first guy is the only one right!
take the second and flip it over and times it instead of dividing
x^2/5 *5/x^7
5x^2/5x^7
Simply
1/x^5
Or dividing by common base leave them out and divide the first terms
x^2/x^7
1/x^5
2007-12-01 11:01:21 · answer #3 · answered by Anonymous · 0⤊ 0⤋
When dividing with a common base, subtract exponents. 2/5-7/5 = -1
so x^/-1 or 1/x
2007-12-01 11:00:26 · answer #4 · answered by Jonathan J 2 · 0⤊ 1⤋
x^2/5 / x^7/5
x^2/5 * 5/x^7= 1/x^5
2007-12-01 11:00:25 · answer #5 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
lol... been many years since I have seen that "Greek". As I read the answers of diversity here, I saw one that was in agreement with the first. What I did learn in tackling math problems (back in the day), was that your answer would be correct and verifiable so as fact, when you apply the "rules" to the problem being solved. This attitude in solving math problems can also be applied to "life lessons", where problems need to be solve, look at the rules. Morrow... know the rules and apply them in your quest for answers.
2007-12-01 11:17:06 · answer #6 · answered by MasterPoet Charliewang 1 · 0⤊ 0⤋
that's the same as x^(2/5-7/5)
=)
i think youc an do the rest now
2007-12-01 11:12:15 · answer #7 · answered by Clueless 5 · 0⤊ 0⤋
I think you would subtract the exponents, but I'm not sure. Sorry! I bet that you could find the answer, or how to do it by searching on google. Or better yet, ask your teacher or a classmate. Sorry I couldn't be of more help.
2007-12-01 11:01:05 · answer #8 · answered by Bobberts 3 · 0⤊ 1⤋
I will agree with ^^^..it's 1/x^5 (babs and james have the same answer i do)
2007-12-01 11:12:36 · answer #9 · answered by Kairi 2 · 0⤊ 0⤋
x^5 maybe...
2007-12-01 11:00:42 · answer #10 · answered by MainelyAs11 2 · 0⤊ 1⤋