spring problem?

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a spring has a spring constant of k=55.0 N/m. The spring is compressed a distance of 3.50 cm. What is the potential energy start in the spring?

2007-12-01 10:40:23 · 2 answers · asked by 832 1 in Science & Mathematics ➔ Physics

2 answers

The first answerer forgot that the force is not a constant over the entire distance but rather increases linearly from 0 to 1.925 N.

Energy = (1/2) (1.925 N) (0.035 m)

2007-12-01 15:30:51 · answer #1 · answered by Tim C 7 · 0⤊ 0⤋

by Hooke's law F = kx = 55 x 0.035 = 1.925 N

PE = mgh = Fd = 1.925 x 0.035 = 0.067 J

2007-12-01 18:59:44 · answer #2 · answered by jamesyoy02 6 · 0⤊ 1⤋