The Law of Sines Question?

Question

Solve the following triangle. Round lengths to the nearest tenth and angle measures to the nearest degree.

B = 5 Degrees, C = 125 Degrees, b = 200

Answer 1

A=50 degrees as the sum of the angles = 180.
By law of sines,
200/sin(5)=AB/sin(125)
AB =200 (sin(125)/sin(5))
=200(0.8192/0.0872)=1878.9
AB/sin(125)=BC/sin(50)
BC=AB sin(50)/sin(125)
=1878.9(0.766)/(0.819)=1752.3
AC/sin(5)=AB/sin(125)
AC=ABsin(5)/sin(125)=134.2

Answer 2

Hi,
The sides are proportional to their sines, so we can write this for c:
b/sinB = c/sinC
c=sinC(b/sinB)
=sin125(200/sin5)
=0.819(200/0.087)
=1882.7
Now, we can write this for a:
a = sinA(200/0.087)
=sin (180-5-125)(200/0.087)
=0.766(200/0.087)
=1760.9
So, side a = 1760.9, side b = 200, side c = 1882.7
Angle A =50, Angle B=5, angle C=50

FE