Physics Question?

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A force of 40.0 N is required to start a 5.0 kg box moving across a horizontal concrete floor. (a) What is the coefficient of static friction between the box and the floor? (b) If the 40.0 N force continues, the box accelerates at 0.70 m/s^2. What is the coefficient of kinetic friction?

Please show and explain all work please.

2007-12-01 08:53:00 · 1 answers · asked by Kantilal P 1 in Science & Mathematics ➔ Physics

1 answers

40=5*9.8*µs
µs=0.816

40-5*9.8*µk=5*0.7

µk= 0.745

j

2007-12-02 07:07:56 · answer #1 · answered by odu83 7 · 0⤊ 0⤋