dont know how to do this
2007-12-01 08:38:59 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Use the quadratic formula:
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a
x = (-7 ± √(49 - 128))/8
x = (-7 ± √(-79))/8
x = (-7 ± i√(79))/8
79 is a prime number and cannot be factored, the solutions are complex numbers.
.
2007-12-01 08:49:43 · answer #1 · answered by Robert L 7 · 0⤊ 0⤋
zeros are values of x for which F(x) =0
so the zeros are solutions of 4x^2+7x+8=0
this has no real solutions for the discriminant (found by b^2-4ac=7^2-4*4*8)is less than 0. So F(x) has No zeros
2007-12-01 08:44:55 · answer #2 · answered by mwanahamisi 3 · 0⤊ 0⤋
You take the derivative of the function and set it to zero then solve for x:
f(x)= 4x² + 7x + 8
f'(x) = 8x + 7 = 0
8x + 7 = 0
8x = -7
x = -7/8
2007-12-01 08:43:38 · answer #3 · answered by Matty B 3 · 0⤊ 0⤋
There are zeros to this function, but they are imaginary. Use the quadratic formula to solve.
2007-12-01 08:47:09 · answer #4 · answered by Anonymous · 0⤊ 0⤋