What is the coefficient of K2Cr2O7 in the balanced equation?
2007-12-01 06:44:09 · 6 answers · asked by Jesse W 1 in Science & Mathematics ➔ Chemistry
1.
already balanced.
the whole thing would be;
1,1,3 to 1,1,1,1
2007-12-01 06:49:19 · answer #1 · answered by Anonymous · 0⤊ 1⤋
2
2007-12-01 07:09:05 · answer #2 · answered by YRAG 1 · 0⤊ 0⤋
Each carbon atom will lose 4 electrons and each molecule of K2Cr2O7 will gain 6 electrons. So, you'll need 3 C and 2 K2Cr2O7.
So, the coefficient for the K2Cr2O7 will be "3".
2007-12-01 07:00:39 · answer #3 · answered by hcbiochem 7 · 0⤊ 0⤋
C goes from 0 to +4
Cr goes from +6 to +3
To balance the electron gain/loss you will need 3 C (3x-4 e)and 4 Cr (4x+3 e)
3C+2K2Cr2O7+8H2SO4--->
3CO2+2K2SO4+2Cr2(SO4)3+8H2O
2007-12-01 07:01:17 · answer #4 · answered by skipper 7 · 0⤊ 0⤋
there will be a 2 in front of K2SO4
2007-12-02 12:49:59 · answer #5 · answered by molchaniezolota 1 · 0⤊ 0⤋
2C+ 2K2Cr2O7+ 5H2SO4----> 2CO2+ 2K2SO4+ Cr(SO4)3+ 5H2O C: 2A=2D K: 2B=2E Cr: 2B=F O: 7B + 4C = 2D +4E +12F +G H: 2C = 2G S: C= E+ 3F solve for A,B,C,D,E,F,G: coefficient of K2SO4: 2
2016-05-27 03:16:51 · answer #6 · answered by ? 3 · 0⤊ 0⤋