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Calculate the maximum wavelength of light capable of removing an electron for a hydrogen atom from the energy state characterized by n=1 and by n=2.

2007-12-01 06:14:41 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

Use the Rydberg formula

1/(mwavelength) = Rh ( 1/na^2 - 1/nb^2)

Rh is the Rydberg constant 1.097x10^7 m^-1

na and nb are integers for the quantum number, n

I'll use w for wavelength

1/w = 1.097x10^7 ( 1/1^2 - 1/2^2)

1/w = 1.097x10^7 m^-1 *( 1 - 1/4)

1/w = 1.097x10^7 m^-1 *( 3/4)

1/w= 8227500

w = 1/(8227500)

w= 1.21x10^ -7 m

if you convert to frequency, v then v will be

2.468x10^15 s^-1

2007-12-01 06:29:15 · answer #1 · answered by obscurusvita 4 · 0 1

You should have an equation that allows you to calculate the difference in the energy of an electron when it moves from one shell to another. In your problem here, you'll be moving an electron from one shell (n=1 or n=2) to an infinite distance (n=infinity).

Once you calculate that energy, just use E=hc/lambda to calculate the wavelength of light that will accomplish that.

2007-12-01 06:29:36 · answer #2 · answered by hcbiochem 7 · 0 0

For the hydrogen atom, En=-hR/n^2

h is Planck's constant, R is the Rydberg constant and n is your energy level. Just plug and chug baby, plug and chug!

2007-12-01 06:24:30 · answer #3 · answered by Anonymous · 1 0

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