If you are solving a real-world problem involving a quadratic equation, and the discriminant is negative, what can you conclude?
2007-12-01 06:05:46 · 4 answers · asked by md_free23 1 in Science & Mathematics ➔ Mathematics
When the discriminant is negative, that means that the quadratic equation has no real solution. Seek another method.
2007-12-01 06:18:42 · answer #1 · answered by Horatio 7 · 0⤊ 0⤋
Then you will have to ignore the imaginary part. Yeah, i know it sounds bad, and probably makes math look bad but in real world problems....you need the imaginary part in order to solve your problem. When you have your solution then you will have to just remove the imaginary part and only work with your real solutions( discrimant equal or greater than 0). This is just my take on it...i could be wrong
2007-12-01 06:22:55 · answer #2 · answered by Brian 6 · 0⤊ 0⤋
Depends upon what the significance of the imaginary part is when associated with that real world problem.
Example, If you consider a real world situation of AC Voltage, resistance and AC Current relationship, an imaginary part in say, current would determine the phase of current (i.e. if if it lags or leads the voltage).
2007-12-01 06:19:40 · answer #3 · answered by Ganesh L 2 · 0⤊ 0⤋
For increasing cubic binomials the prevalent formulation is as follows: (a + b) ^ 3 = a^3 + 3*a^2*b^a million + 3*a^a million*b^2 + b^3 on your case, a is x and b is -y^5 So (x - y^5)^3 = x^3 + 3*x^2*(-y^5)^a million + 3*x^a million*(-y^5)^2 + (-y^5)^3 Simplified: =x^3 - 3x^2*y^5 + 3x*y^10 - y^15 :D
2016-10-18 12:07:48 · answer #4 · answered by Anonymous · 0⤊ 0⤋