a diamond a queen
2007-12-01 05:46:17 · 6 answers · asked by b m 1 in Science & Mathematics ➔ Mathematics
Well, it depends on exactly what you mean. If you mean, what are the odds of getting a diamond OR a queen, then there are 13 diamonds, and 3 queens that aren't diamonds. That's 16 possible cards out of 52, so the odds are 16/52 = 8/26 = 4/13.
Another way of looking at this answer is that it's the sum of the odds of getting a diamond, plus the odds of getting a queen, minus the odds of getting the queen of diamonds (1/52), since we don't want to count that one card twice.
The odds of getting a diamond of any rank are 13/52 = 1/4, and the odds of getting a queen of any suit are 4/52 = 1/13.
2007-12-01 05:55:04 · answer #1 · answered by Your Friendly Neighborhood Skip 3 · 0⤊ 1⤋
P(diamond) = 13/52 = 1/4
P(queen) = 4/52 = 1/13
2007-12-01 05:50:38 · answer #2 · answered by Philo 7 · 1⤊ 2⤋
A diamond: 13/52
A queen: 4/52
The queen of diamonds: 1/52
2007-12-01 05:52:08 · answer #3 · answered by Joe L 5 · 1⤊ 1⤋
a diamond 13/52 (no jokers here)
a queen 4/52 (queen for a day)
2007-12-01 05:51:31 · answer #4 · answered by answerING 6 · 1⤊ 1⤋
if you are looking for a queen then it will be
4/52 or 1/13 chance
if you are looking for a diamond it will be
13/52 or 1/4 or 25% chance
but if you are looking for a queen that is a diamond
1/52
2007-12-01 05:50:18 · answer #5 · answered by Ms. Exxclusive 5 · 1⤊ 1⤋
P(diamond) = 1/4
P(queen) = 1/13
2007-12-01 08:59:27 · answer #6 · answered by Como 7 · 3⤊ 1⤋