Question 1
8y + 5y = 26
13y = 26
y = 2
x = 8 , y = 2
Question 2
7x = 21
x = 3
12 + 2y = 8
2y = - 4
y = - 2
x = 3 , y = - 2
2007-12-01 06:27:12
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answer #1
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answered by Como 7
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2(4y) + 5y = 26
13y = 26 y = 2
2 x 4 = 8 x = 8
-13 + 3x + 4x = 8
21 = 7x x = 3
3 x 4 = 12 12 + -4(-2[2])= 8 y = -2
2007-12-01 11:50:34
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answer #2
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answered by ViewtifulJoe 4
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1) x=4y, 2*4y +5y=26.
13y=26, y=2. x= 4y= 4*2=8. x=8, y= 2.
2) 3x-2y=13
4x +2y=8
Add 7x=21, x=3. 3*3 -2y=13, -2y= 13-9=4, y= -2.
x= 3, y= -2.
2007-12-01 13:59:10
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answer #3
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answered by Sasi Kumar 4
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x = 4y
2x + 5y = 26
2(4y) + 5y = 26
8y + 5y = 26
13y = 26
y = 2
x = 4y
x = 4(2)
x = 8
intersection: (8,2)
3x-2y=13
4x+2y=8
add down:
7x = 21
x = 3
replace into either equation:
3(3) - 2y = 13
9 - 2y = 13
-2y = 4
y= -2
or
4(3) + 2y = 8
12 + 2y = 8
2y = -4
y = -2
intersection: (3,-2)
2007-12-01 11:41:00
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answer #4
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answered by sayamiam 6
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2x+5y=26
2(4y)+5y=26 (subsitute the x value in for the x)
8y+5y=26
13y=26
y=2 (divide both sides by 13)
2x+5(2)=26 (subsitute the Y value in)
2x+10=26
2x=16 (subtract the 10 from both sides)
x=8 (divide both sides by 2.)
Y=2, X=8
I am going to asume this is what you had to do.
2007-12-01 11:47:43
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answer #5
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answered by Anonymous
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1.x=4y
2x+5y=26 we put where x=4y and we have:
2*4y + 5y=26
8y + 5y=26
13y=26
y=26/13
y=2
so x=4y
x=4*2
x=8
so (x,y)=(8,2)
2. 3x-2y=13
4x+2y=8
By addition of the two equations we take:
3x - 2y + 4x + 2y = 13 + 8
7x = 21
x=21/7
x=3
so from the first equation we have:
3x - 2y = 13
3*3 -2y = 13
9 - 2y = 13
-2y = 13 - 9
-2y = 4
y=-2
so (x,y)=(3,-2)
2007-12-01 11:40:01
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answer #6
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answered by Orfeas 3
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