2007-12-01 02:05:11 · 6 answers · asked by jes 1 in Science & Mathematics ➔ Mathematics
2x + 3y = 7
3y = - 2x + 7
y = (-2/3)x + 7/3
m1 = - 2/3
m2 = - 2/3
y + 2 = (- 2/3) (x + 3)
y = (- 2/3) x - 2 - 2
y = (- 2/3) x - 4
2007-12-01 03:13:12 · answer #1 · answered by Como 7 · 3⤊ 1⤋
2x - 3y = 7.................( a million ) want this in usual kind so - 3y = 7 - 2x 3y = 2x - 7 y = (2/3)x - 7/3 so the gradient ( slope) of ( a million) is two/3 and this can be the gradient of the recent line because this is to be parallel to ( a million). So the equation of the recent line might want to be written as y = (2/3)x + c the position c is a continuing because the line passes by ability of ( -2 , 2) we get 2 = (2/3)( -2 ) + c after multiplying by ability of by ability of three we get 6 = -4 + ok ( ok = 3c) => ok = 10 so required equation is y = (2/3)x + 10 or 3y = 2x + 30
2016-10-25 06:09:19 · answer #2 · answered by labarriere 4 · 0⤊ 0⤋
Step 1) Change 2x + 3y=7 to an equation that solves for Y, which would be 3y= -2x + 7.
Step 2) Instead of solving for 3y, you want to solve for Y, so divide both sides by 3, which would give you "y= -2/3x + 7/3."
Step 3) Since the equation you want to create passing through the given coordinates must be parallel to this equation, this means that it also has the same slope of -2/3x, but a different y intercept.
Step 4) Using the slope-intercept equation format, y = mx + b, you plug in all the information you have already for the equation you want to create. You have the x and y coordinates, so you plug those in for x and y. You have the slope, -2/3, so you would plug that in for m. Now, you need to solve for the last remaining variable, b, which is the symbol for the y-intercept. You equation should look like this:
-2= -2/3(-3) + b.
Step 5) When you solve for b, you would get "-4" as your answer. Now plug in the slope and y-intercept leaving out the x and y values. Your equation would be: y = -2/3x - 4.
2007-12-01 02:33:51 · answer #3 · answered by Kal 1 · 0⤊ 2⤋
The parallel line must have a slope of -2/3 and your point (-3, -2) must lie on it, so
-2 = (-2/3)(-3) + b making b = -4
Your line is y = (-2/3)x + (-4)
2007-12-01 02:12:14 · answer #4 · answered by answerING 6 · 1⤊ 0⤋
2x + 3Y=7 i.e
y=-2/3 x+7 this line is paralle to y=-2/3x so
the equation it mast be
y=-2/3x+b but for x=-3 it mast be y=-2 so
-2=-2/3*(-3)+b i.e -2=2+b i.e b=-4
so y=-2/3x-4 or 3y=-2x-12
or 3y+2x=-12
2007-12-01 02:13:31 · answer #5 · answered by Kulubaki 3 · 1⤊ 1⤋
bcos the slope of given eq is -2/3, so
y+2=-2/3(x+3). Now u can solve it
2007-12-01 02:12:36 · answer #6 · answered by Ahmed Zia 3 · 1⤊ 1⤋