are these lines parallel, perpendicular or neither?
2007-12-01 01:59:52 · 8 answers · asked by jes 1 in Science & Mathematics ➔ Mathematics
Line 1
3y = 2x + 6
y = (2/3) x + 2
Line 2
y = (2/3)x + 1
Lines have same gradient (slope) of 2/3 so they are parallel.
2007-12-01 03:21:44 · answer #1 · answered by Como 7 · 3⤊ 1⤋
Parallel. If you divide the 3y by 3 in the first eqn to get an equivalent equation the gradient becomes - 2/3 x.
So the gradients are the same
2007-12-01 02:03:01 · answer #2 · answered by ►Aurora Borealis 5 · 1⤊ 1⤋
They are parallel because if you put the 1st line in slope intercept form it is 3y= 2x+ 6 then divide it then both lines have the same slope after you divide it so it is parallel
2007-12-01 02:05:12 · answer #3 · answered by Anonymous · 0⤊ 1⤋
Parallel lines have the same slope.
Solve the one equation for y and you get the following:
y = 2/3x + 2
The other equation is the following:
y = 2/3x +1
SO, same slope, parallel lines
2007-12-01 02:04:40 · answer #4 · answered by fenx 5 · 1⤊ 1⤋
They are parallel because they have the same slope but different y-intercepts.
2007-12-01 02:04:34 · answer #5 · answered by Homer S 1 · 1⤊ 1⤋
parallel
2007-12-01 02:05:56 · answer #6 · answered by rrr 2 · 0⤊ 1⤋
parallel
2007-12-01 02:02:12 · answer #7 · answered by HI!!!!!! 3 · 2⤊ 1⤋
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2007-12-01 02:08:40 · answer #8 · answered by Ahmed Zia 3 · 0⤊ 2⤋