(2x+3)/2=5 - (2(x-4))/3
Right hand side = 5 - [ 2 ( x - 4 ) ] divided by 3
=> 5 - [ (2 x - 8) / 3 ] = ( 15 - 2x + 8 ) / 3 = (23 - 2x) / 3
Left hand side = [ 2 x + 3 ] divided by 2
But according to the question Left hand side = Right hand side
ie [ 2 x + 3 ] divided by 2 = (23 - 2x) / 3
ie 2 ( 23 - 2x ) = 3 ( 2x + 3 )
ie 46 - 4x = 6x + 9
ie 46 - 9 = 6x + 4x
ie 37 = 10 x
ie x = 37/10 = 3.7 ................ Answer
check : Substitute 3.7 for x in the original eqn :
=> [2(3.7) + 3] / 2 = 5 - [ 2 ( 3.7 - 4 ) ] / 3
=> [ 7.4 + 3 ] / 2 = 5 - [ 2 ( - 0.3 ) ] / 3
=> (10.4) / 2 = 5 - [ - 0.6 ] / 3
=> 5.2 = 5 + 0.2
=> 5.2 = 5.2 verified.
2007-12-01 05:36:49
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answer #1
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answered by Pramod Kumar 7
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LHS always equals RHS
So
(2x+3)/2=LHS
5- (2(x-4))/3 = RHS
Solve LHS
It actually remains as written, that is (2x + 3) / 2
Solve RHS
{Remember BODMAS}
5 - [{2x - 8} /3]
[{15 - 6x - 24 } / 3]
Put them back together
[(2x + 3) / 2]=[{15 - 6x - 24 } / 3]
"Cross Multiply"
[3 (2x + 3] = [2(-9 - 6x)]
6x + 9 = -18 - 12x
18x = -27
x= - 27/18
x = 1.5 {Tah Rah}
Hope this helps :-)
2007-12-01 00:38:17
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answer #2
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answered by Rod Mac 5
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(2x + 3)/2 = 5 - [2(x - 4)/3]
(2x + 3)/2 = (23 - 2x)/3
3(2x + 3) = 2(23 - 2x)
6x + 9 = 46 - 4x
10x = 37
x = 37/10
2007-12-01 00:31:34
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answer #3
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answered by Akilesh - Internet Undertaker 7
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(2x+3)/2 = 5 - (2(x-4))/3
(2x+3)/2 = 5 - (2x - 8)/3
[3(2x+3)]/6 = 15 - [2(2x-8)]/6
(6x+9)/6 = 15 - (4x - 16)/6
(6x+9 - 4x - 16)/6 = 15
(2x - 7)/6 = 15
2x-7 = 90
2x=97
x=48.5
Voila!
2007-12-01 00:48:19
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answer #4
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answered by Kenneth Koh 5
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2016-10-18 11:24:50
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answer #5
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answered by Anonymous
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(2x+3)/2=5- (2(x-4))/3
6x+9=30-4x+16
10x=37
x=3.7
2007-12-01 00:33:55
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answer #6
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answered by Anonymous
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multiply both sides by 6
6x+9 =30 -4x +16
10x = 37
x=3.7
2007-12-01 00:32:19
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answer #7
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answered by mbdwy 5
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(2x+3)/2=5-(2(x-4))/3
(2x+3)/2=5-(2x-8)/3
(2x+3)/2=(15-2x+8)/3
(2x+3)/2=(23-2x)/3
(2x+3)3=(23-2x)2
6x+9=46-4x
6x+4x=46-9
10x=37
x=37/10
x=3.7
2007-12-01 00:35:44
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answer #8
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answered by sadhana s 2
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x=3.7
2007-12-01 00:44:48
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answer #9
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answered by Grampedo 7
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