math help finding inverse?

Question

find inverse of


f(x) = 2x + 3/ x+2

I set up to solve for Y and can't get the rught anwser, how do you do this??/

Answer 1

let f(x) = y, then your function looks like:
y = 2x + 3/(x+2) - i assume that x + 2 is in the denomianator

to find inverse swap x with y:

x = 2y + 3/(y+2) and solve for y

if this is the case, then the problem is quite difficult, unless what you meant was:
y= (2x + 3)/(x + 2)

then inverse: x = (2y + 3)/(y + 2)
now solving for y will give us:
y = (3 - 2x)/(x - 2)

remember to use brackets when writing fractions!!

Answer 2

I think for an expression y = 2x + 3/x + 2 (same thing as yours I just changed f(x) for y) switch the y's for x's and the x's for y's

so you get this: x = 2y + 3/y + 2 then solve for the y and the result is your inverse.. (You do this part I'm tired.)

Answer 3

2x+3=x+2 x=-1

Answer 4

F(X) can mean the same thing as Y. What do you mean inverse? Are you trying to find the inverse of that equation? No matter what, you will most likely have to set the equation to zero and then solve.

Answer 5

>>basically elect for to envision my ideas Oh, if I had a nickel for each and each and every time I heard THAT line actual right here! f = ?(12-2x) f^2 = 12 - 2x f^2 - 12 = -2x (f^2 - 12) / -2 = x x = (12 - f^2) / 2 So g(x) = (12 - x^2) / 2

Answer 6

y = (2x+3)/(x+2)
Switch x and y,
x = (2y+3)/(y+2)
=> xy+2x = 2y+3
Solve for y,
y = f^-1(x) = (2x-3)/(2-x)

Answer 7

Let f(x) = y
y = (2x + 3) / (x + 2)
xy + 2y = 2x + 3
xy - 2x = 3 - 2y
x(y - 2) = 3 - 2y
x = (3 - 2y) / (y - 2)
f^(-1) (y) = (3 - 2y) / (y - 2)
Thus
f^(-1)(x) = (3 - 2x) / (x - 2)