how do you solve for x in the equation 10^x = 0.1
2007-11-30 18:59:29 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Multiply both sides by 10^2 = 100
10^x * 10^2 = 10
10^(x+2) = 10^1
equate exponents.
x+2 = 1
x = -1
2007-11-30 19:01:56 · answer #1 · answered by Demiurge42 7 · 2⤊ 3⤋
Take log base 10 of both sides:-
x = log (0.1)
x = - 1
2007-11-30 21:41:46 · answer #2 · answered by Como 7 · 3⤊ 0⤋
10^x=0.1
but 0.1 = 1/10 =10^(-1)
so 10^x=10^(-1)
so x = -1
2007-11-30 19:08:37 · answer #3 · answered by Diana B 2 · 0⤊ 1⤋
you have to make one side look like the other by making the 0.1 change into 10^-1 and then you find out the value of x =-1
10^x=0.1
10^x=10^-1
so x=-1
2007-11-30 19:11:45 · answer #4 · answered by princesskatty 1 · 0⤊ 2⤋
log(10^x) = log(0.1)
x = -1
2007-11-30 19:04:09 · answer #5 · answered by a²+b²=c² 4 · 0⤊ 1⤋