A person measures the angle of depression from the top of the wall to a point on the ground. the point is located on the level ground 62 feet from the base of the wall and the angle of depression is 52 degrees. how high is the wall to the nearest foot.
i cant picture this question plz explain and show me how to do it plz.
2007-11-30 16:48:53 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Draw triangle ABC right angled at B
AB is height of wall
BC = 62 ft is horizontal
/_A = 38°
tan 38° = 62 / AB
AB = 62 / tan 38°
Height = 48 ft (to nearest foot)
2007-11-30 22:34:06 · answer #1 · answered by Como 7 · 3⤊ 1⤋
90-52=38
The opposite side of 38 degrees is 62ft
tan38=62/height
height=79 ft(to nearest ft)
2007-12-01 00:54:11 · answer #2 · answered by someone else 7 · 1⤊ 1⤋
48.439 feet
Tan = SO / SA
the side opposite is the 62 feet and the side adjacent is the wall.
tan of 52 deg is 1.2799.........62 / 1.2799 = 48.439 ft
2007-12-01 00:58:27 · answer #3 · answered by Rich 7 · 1⤊ 2⤋