A ship on the ocean surface detects a sunken ship on the ocean floor at an angle of depression of 50 degrees. the distance between the ship on the surface and the sunken ship on the ocean floor is 200 meters.if the ocean floor is level in this area,how far abouve the ocean floor to the nearest meter ,is the ship on the surface?
i got tan50 200/1.191 and got x equals 168 M but i dont know if i am right,can you guys plz correct me , i m just getting the hang of this.
2007-11-30 15:45:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Just remember SOH CAH TOA. Sin is Opposite over Hypotenuse. Cos is Adjacent over Hypotenuse. Tan is Opposite over Adjacent. Drawing diagrams help.
2007-11-30 15:49:44 · answer #1 · answered by lmpitcher9 3 · 0⤊ 1⤋
ship on surface---
=============ship submerged-
I think you want to use a sine function: sin 50 = y/200
y = 153.209 meters
The 200 meters is the diagonal hypotenuse (that can't be drawn here). That diagonal makes a 50 deg angle with the top horizontal water surface. The vertical distance between the water surface and the horizontal ground the submerged ship lies on is what you're after.
2007-12-01 00:10:49 · answer #2 · answered by answerING 6 · 0⤊ 0⤋
If all else fails, draw a sketch.
depth = 200sin(50°)
depth â 153.2 m
2007-12-01 00:06:43 · answer #3 · answered by Helmut 7 · 0⤊ 0⤋
tan(50º) = 1.192
sin(50º) = 0.7660 / cos(50º) = 0.6427
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looks good !
2007-11-30 23:55:23 · answer #4 · answered by JavaScript_Junkie 6 · 0⤊ 0⤋