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A home heating system can supply energy at the maximum rate of 26 kW. If the house loses energy at the rate of 6.5 kW per °C of temperature difference between interior and exterior, what's the minimum outdoor temperature at which the heating system can maintain 22°C (71.6°F) indoors?

2007-11-30 13:59:00 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

26 Kw/6.5Kw per degree = 4 degrees C

2007-11-30 14:03:30 · answer #1 · answered by Tim C 7 · 0 1

The house will lose heat energy at the rate of (22 - T)*6.5, where T is the outdoor temp. This must equal the energy input of the heater if the temp is to remain constant, so

(22 - T)*6.5 = 26

solve for T

2007-11-30 14:05:16 · answer #2 · answered by gp4rts 7 · 0 0

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