2007-11-30 13:22:52 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
h = 0.5 g t^2
g = 32.2 ft/s^2
h = 0.5 (32.2)(5)^2
= 16.1(25)
= 402.5 ft
2007-11-30 13:28:48 · answer #1 · answered by vlee1225 6 · 1⤊ 0⤋
s = (1/2) a t^2 and t = 5
2007-11-30 13:28:43 · answer #2 · answered by Tim C 7 · 0⤊ 0⤋
The distance traveled by ball is given by
s = ut + gt^2/2
s = distance
u, initial velocity = 0
t, time = 5 sec
g,acceleration due to gravity = 9.8 meters/sec^2
So, s = 9.8(5^2)/2 meters
s = 9.8(25)/2 = 122.5 meters
2007-11-30 13:42:12 · answer #3 · answered by mohanrao d 7 · 1⤊ 0⤋
Kemmy &vlee1225 are both right because 1ft=.3048m, but the acceleration due to gravity in metric is 9.8 m per second squared to more significant digits, which accounts for the difference between the two answers
2007-11-30 13:37:16 · answer #4 · answered by Louise 3 · 0⤊ 0⤋
Initial velocity, u=0
Acceleration due to gravity, a=10m/s2
Time, t = 5s
Height, s = ?
s = ut + (1/2)at^2
s = 0 + (1/2)(10)(5^2)
s = 125m
2007-11-30 13:28:47 · answer #5 · answered by Kemmy 6 · 0⤊ 0⤋
vlee is right. The problem uses a ball, so air friction is negligible. Therefore, weight of the ball has very little effect ang can be ignored.
2007-11-30 13:45:00 · answer #6 · answered by krazykyngekorny 4 · 0⤊ 0⤋
h = height of window
h = 1/2gt squared
h = 1/2(32.2)(5)(5)
H =16.1(25)
h = 402.5 feet
2007-11-30 13:38:32 · answer #7 · answered by Anonymous · 0⤊ 0⤋
9.8 meters per second. 9.8 x 5 = 45 + 4 .... 49 meters high
2007-11-30 13:49:58 · answer #8 · answered by ViewtifulJoe 4 · 0⤊ 0⤋
Depends on the weight of the ball.
2007-11-30 13:31:15 · answer #9 · answered by starwarschick148 2 · 0⤊ 4⤋
It depends what kind of ball it is. Because objects fall fast when they're heavy.
2007-11-30 13:28:34 · answer #10 · answered by milkjilk 1 · 0⤊ 6⤋