Help with math question:?

Question

Please help me, I am so lost and confused:
I have to do polynomials

16m^3n^3 + 24m^2n^2 - 40mn^3 divided by 8mn^2

If you can help, please help!

Answer 1

you need to find the term that will completely divide into all terms of the denominator and numerator.

that term is 8mn^2. so basically, take that term and divide each part of the numerator, remember that coefficients divide like normal and exponents subtract from each other!

2m^2n + 3m - 5n

hope that helps.

Answer 2

Yep. Just factor the first term like this:

8mn^2 (2m^2n +3m -5n) = 16m^3n^3 + 24m^2n^2 - 40mn^3

now when you divide, the 8mn^2 cancels out to 1 and you are left with what's in the brackets.

Easy when you know how! Answer is: 2m^2n +3m -5n

Answer 3

16m^3n^3 + 24m^2n^2 - 40mn^3 divided by 8mn^2

the qoutient is 2m^2n+3m-5n
the reminder is 0


check
multiply the quotient 2m^2n+3m-5n with 8mn^2
16m^3n^3 + 24m^2n^2 - 40mn^3
so the answer is right

Answer 4

[16m^3n^3 + 24m^2n^2 -- 40mn^3 ] / 8mn^2
= 16m^3n^3/8mn^2 + 24m^2n^2/8mn^2 -- 40mn^3/8mn^3
= 2m^2n + 3m -- 5

Answer 5

8mn^2 (2m^2n + 3m-5n) = 16m^3+24m^2n^2-40mn^3)

Answer: 2m^2n + 3n - 5n

Answer 6

you have to divide this by long division

the quotient is 2m^2n+ 3m^2 -5

and the remainder is 0

Answer 7

(2m^2n+3m-5n)(8mn^2)/(8mn^2)

Therefore (2m^2n+3m-5n) since the other part cancels