I think it's
999999999999999999990
Hope that helps.
2007-11-30 08:07:47
·
answer #1
·
answered by pyz01 7
·
2⤊
0⤋
The sum of each column is 90 because you have twice the sum of 0 through 9 (which is 9 x 10 / 2 = 45).
Given there are 20 columns, this would equal:
90 x 11,111,111,111,111,111,111.
Equivalently you can write:
99,999,999,999,999,999,999 x 10
Answer:
999,999,999,999,999,999,990
(20 nines followed by a zero)
2007-11-30 08:10:04
·
answer #2
·
answered by Puzzling 7
·
3⤊
0⤋
Alright here goes (sigma) 0 -9 = Sum of numbers 0-9 and that is 45 * 42 - 9 = 1881.
2007-11-30 08:16:54
·
answer #3
·
answered by rcds23 6
·
0⤊
0⤋
Sum of integers from 1 to 10 = (10)*(1+10)/2 = 55
The numbers from 1 to 10 appear twice in each column, so each column adds to 110.
So first column on right ends in 0, and carries 11.
Second column from right adds to 110, plus 11 = 121.
So second column ends in 1, and carries 12.
Continuing this way, all 20 columns end in 1, with leftmost having an extra 29
So I get 29, followed by 20 ones
2007-11-30 08:13:46
·
answer #4
·
answered by fcas80 7
·
0⤊
2⤋
the total would be 1400 because each row is the same amount since it has the same numberes just different numbers so each row equals 70 and there is 20 rows so 70 times 20 is 1400
2007-11-30 08:19:20
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
999999999999999000000, as per excel
A much better question would be, Why is it that no matter how you look at the above pattern, the 1's are always in the light areas, and the 7-8-9's are shaded?
2007-11-30 08:10:50
·
answer #6
·
answered by Anonymous
·
0⤊
1⤋
If you look at that bunch of numbers crosseyed it has a neat diagonal pattern.
2007-11-30 08:07:43
·
answer #7
·
answered by KeplJoey 7
·
0⤊
0⤋
each column adds up to 90, and each row has 18 numbers, so its
90+900+9000+...+9x10^18, so its 999999999999999990
2007-11-30 08:14:41
·
answer #8
·
answered by The Source 2
·
0⤊
1⤋
well, it's approximately:
5.0*10^21
2007-11-30 08:11:20
·
answer #9
·
answered by pstwoorbust 3
·
0⤊
2⤋