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Assuming atmospheric pressure to be 1.01 x 10^5 Pa and the density of sea water to be 1025 kg/m^3, what is the absolute pressure at a depth of 15m below the surface of the ocean?

2007-11-30 07:13:23 · 5 answers · asked by Anonymous in Science & Mathematics Physics

5 answers

The increase of pressure with depth in a fluid is pgh where p is the density of the fluid. The absolute pressure is the increase in pressure, plus the pressure at the top (1 atmosphere in your problem). So,

P = 1.01 x 10^5 Pa + ( 1025 kg /m^3 )( 9.8 m/s^2 )( 15 m )

2007-11-30 07:20:55 · answer #1 · answered by jgoulden 7 · 2 0

brenna,

a good number to remember to "check" your answer is that for every 10 m down, pressure increases by 1 atmosphere (1.01E5Pa). Of course you need to add the 1 atmosphere of the atmosphere.

2007-12-01 00:44:07 · answer #2 · answered by Anonymous · 0 0

If it is so easy, then why are you asking US? If there is a physics tutoring room at your college, you might try asking there...

2007-11-30 15:17:02 · answer #3 · answered by Anonymous · 0 1

brenna brenna bobenna banana bana bo benna....physics is all around us

2007-11-30 15:16:53 · answer #4 · answered by Anonymous · 0 2

i don't know but add jasonroberts1993@hotmail.co.uk

2007-11-30 15:17:27 · answer #5 · answered by Jason R 1 · 0 2

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