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A. - 9a + 5b + 6
B. 9a + 5b + 6
C. 9a - 5b + 6

2007-11-30 07:04:24 · 9 answers · asked by *:)* 1 in Science & Mathematics Mathematics

9 answers

Hi,

For this question first distribute the -3 over the factor 3a - 5b to get:

-9a + 15b + 6 - 10b

Now, at this point, combine like terms by adding/subtracting terms that are similar to get:

-9a + 5b + 6 <==== FINAL ANSWER or Choice A

I hope that helps you out! Please let me know if you have any other questions!

Sincerely,

Andrew

2007-11-30 07:23:16 · answer #1 · answered by The VC 06 7 · 0 1

Simplifying
-3(3a + -5b) + 6 + -10b
(3a * -3 + -5b * -3) + 6 + -10b
(-9a + 15b) + 6 + -10b

Reorder the terms:
6 + -9a + 15b + -10b

Combine like terms: 15b + -10b = 5b
6 + -9a + 5b

so your answer is( A)

2007-11-30 19:07:30 · answer #2 · answered by Anonymous · 0 1

-9a+15b+6-10b=0
-9a+5b+6
answer is A.

2007-11-30 16:01:28 · answer #3 · answered by surmy 2 · 0 1

Your answer is "a".

Multiply -3 by each term inside the parenthesis (3a-5b).
(-3(3a)-3(-5b))+6-10b

Complete the multiplication of -3 by each term inside the parenthesis.
(-9a+15b)+6-10b

Since 15b and -10b are like terms, add -10b to 15b to get 5b.
-9a+5b+6

Hope this helps.

2007-11-30 15:15:48 · answer #4 · answered by stringsdepotplus 2 · 0 2

distribute the -3 into the parentheses.

-9a + 15b + 6 - 10b
now combine like terms.

-9a + 5b + 6

there it is.... answer A

2007-11-30 15:09:50 · answer #5 · answered by Anonymous · 0 2

- 9a + 15b - 10b + 6
-9a + 5b + 6
OPTION A

2007-12-04 13:47:03 · answer #6 · answered by Como 7 · 0 1

-3(3a-5b) + 6 -10b
-9a+15b + 6 -10b
-9a+5b+6

(a)

2007-11-30 15:18:41 · answer #7 · answered by james w 5 · 0 2

-9a+15b+6-10b
A) -9a+5b+6

*don't forget to multiply the negative with the three!

2007-11-30 15:09:02 · answer #8 · answered by pstwoorbust 3 · 0 2

Distribute
Combine like terms

TALK WITH YOUR TEACHER, please. You obviously need more assistance with this concept, based on the questions you've posted here and in homework help.

2007-11-30 15:13:57 · answer #9 · answered by Anonymous · 0 1

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