If they sold 605 tickets at full price ($8) they would have made
$4840.
But they made $3748.
$4840 - $3748 = 1,092
Divide 1092 / 3 = 364 tickets sold at reduced prices and 241 at regular prices.
You can also do this with algebra:
Let S be the number of reduced price senior tickets.
Let T be the number of regular tickets.
S + T = 605
5S + 8T = 3748
Now solve for S:
S = 605 - T
Substitute into the second equation:
5(605 - T) + 8T = 3748
3025 - 5T + 8T = 3748
3T + 3025 = 3748
3T = 723
T = 723 / 3
T = 241
Then solve for S:
S = 605 - T
S = 605 - 241
S = 364
Either way the answer is:
241 tickets at full price
364 tickets at the senior price
2007-11-30 04:16:32
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answer #1
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answered by Puzzling 7
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Regular price = $8
Senior = $5
Let S = the number of senior tickets sold
The number of regular tickets sold is 605 - S
Revenue = 5 S + (605 - S) * 8 = 3748
5S + 4840 - 8S = 3748
-3S = -1092
S = 364
364 senior tickets and 241 regular priced tickets were sold.
2007-11-30 12:23:50
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answer #2
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answered by Hiker 4
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OK
Full price tickets = 8 = a
Senior discount tickets =8-3=5 =b
a+b = 605
8a + 5b = 3748
Use substitution
a = 605-b
8(605-b) + 5b = 3748
4840 - 8b + 5b = 3748
-3b = -1092
b = 364
So there were 364 senior discount tickets sold.
605 - 364 = a ; a = 241
There were 241 full price tickets sold.
Proof
8(241) + 5(364) = 3748??
1928 + 1820 = 3748??
3748 = 3748 YES!!
Hop that helps.
2007-11-30 12:20:02
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answer #3
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answered by pyz01 7
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I HATE math! But I LOVE the challange!
My guess is: 241 tickets @ $8.00
364 tickets @ $5.00
I have to tell you the reason that I said "My guess it:", is that I'm not sure how I arrived at this. I know there is a logical way and I don't know what it is....
For whatever reason, I did this:
605 tickets X $8.00 = $ 4,840
605 tickets X $5.00 = $ 3,025
$4,840 minus $3,025 = $1815
Total Revenue $ 3,748 minus $1,815 = $1,933
$1,933 divided by $8.00 ticket = 241
605 total tickets minus 241 tickets= 364 tickets
I would also like to know the correct way to arrive at the answer. I hope someone can show us.
2007-11-30 12:41:12
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answer #4
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answered by Rocky 4
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r = # of regular tickets
s = + of senior tickets
the theater sold 605 tickets
1) r + s = 605
s = 605 - r
and took in 3748 in revenue
2) 8r + 5s = 3748
8r + 5(605 - r) = 3748 {substitute for s from eq 1}
8r + 3025 - 5r = 3748
3r = 723
r = 241
1) s = 605 - 241
s = 364
Check
8(241) + 5(364) = 3748
1928 + 1820 = 3748
3748 = 3748
2007-11-30 12:22:31
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answer #5
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answered by kindricko 7
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solution:
let x = number of non senior , y = number of ticket for seniors
since Seniors receiving a discount of 3.00 = 8 - 3 = 5
x + y = 605 (eq1)
8x + 5y = 3748 (eq2)
from eq 1,
x = 605 - y (eq3)
substitute x in eq 2,
8x + 5y = 3748
8 ( 605 - y ) + 5y = 3748
4840 - 8y + 5y = 3748
combined like terms, the unknow must be in possitive form, we have
4840 - 3748 = 8y - 5y
1092= 3y
364 = y number of seniors.
solve fo x, used eq 1 or eq 3 to solve for x,
i used eq 3,
x = 605 - y
x = 605 - 364
x = 241 is the number of non seniors.
2007-11-30 12:26:37
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answer #6
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answered by Anonymous
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605*8 = 4840 <- what they would have made at full time
4840-3748 = 1092 <-different due to seniors
1092/3 = 364 <- total senior tickets sold
605-364 = 241 <- total regular tickets sold
proof:
241(8) + 364(5) = 3748
2007-11-30 12:24:20
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answer #7
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answered by clint 5
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Let there be x seniors and y adults
x+y=605 -- (1)
5x+8y=3748 -- (2)
solve for x and y
from (1) y=605-x
Plug into (2)
5x+8(605-x)=3748
5x+4840-8x=3748
-3x=-1092
x=364 (seniors)
y=241 (using (1))
2007-11-30 12:19:39
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answer #8
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answered by cidyah 7
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x - number of $8 tickets
y - number of $5 senior tickets
x + y = 605
8x + 5y = 3748
solve the two eqn:
x = 241, y = 364
2007-11-30 12:21:02
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answer #9
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answered by tj is cool 5
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8x + 5Y = 3748
x+y = 605
x = 605 - y
8(605-y)+5y=3748
4840-8y+5y=3748
4840-3y=3748
3y=4849-3738=1092
y=1092/3=364
x+364=605
x=241
241 adults and 364 seniors
2007-11-30 12:22:47
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answer #10
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answered by David H 1
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