x+1/3-1/2=3x-3/6
i got this answer
x=4/2=2/1=2
is it right?
2007-11-30 04:02:07 · 11 answers · asked by ihurtmyhand 4 in Science & Mathematics ➔ Mathematics
x + 1/3 - 1/2 = 3x - 3/6
Multiply everything by 6 to remove fractions:
6x + 2 - 3 = 18x - 3
Subtract 6x from both sides:
-1 = 12x - 3
Add 3 to both sides:
2 = 12x
Divide both sides by 12:
2/12 = x
Reduce:
x = 1/6
As a double-check, plug in the value of x back into the equation:
Left side:
1/6 + 1/3 - 1/2
= 1/6 + 2/6 - 3/6
= 3/6 - 3/6
= 0
Right side:
3(1/6) - 3/6
= 3/6 - 3/6
= 0
Since the sides balance that tells us that the answer is correct:
x = 1/6
2007-11-30 04:06:40 · answer #1 · answered by Puzzling 7 · 0⤊ 0⤋
To check your answer just substitute your answer for x into the equation.
2 + 1/3 -1/2 = 3(2)-3/6
change all denominators to 6 and you get
2+2/6-3/6 =3(2)-3/6
2-1/6=6-3/6
so you can see this will not be right
so go back and start over but keeping all denominators in 6's you get
x+ 2/6-3/6=3x-3/6
x-1/6=3x-3/6
add 3/6 to each side and you get
x+2/6=3x
substract x from both sides and you get
2/6=2x
divide each by 2 and you get 1/6=x
To check again
1/6+2/6-3/6 which equals 0
and 3(1/6)-3/6 also equals 0 so your answer should be
x=1/6
2007-11-30 12:12:44 · answer #2 · answered by David H 1 · 0⤊ 0⤋
x+1/3 - 1/2 = 3x - 3/6
solution:
combined like terms,
1/3 - 1/2 + 3/6 = 3x - x
lcd = 6
(2 - 3 + 3) / 6 = 2x
2 / 6 = 2x
cross multiply,
2 = 12 x
1 / 6 = x is the answer
2007-11-30 12:06:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋
No, if you put 2 in to both formulas you get two different answers. Here is a way to work it:
x+1/3-1/2 = 3x-3/6
x-1/6 = 3x-3/6
x=3x-1/3
-2x = -1/3
-x = -1/6
x=1/6
(1/6)+1/3-1/2 = 3(1/6)-3/6
Both sides are equal to zero. Hope this helps...
2007-11-30 12:10:33 · answer #4 · answered by clint 5 · 0⤊ 0⤋
x+1/3-1/2=3x-3/6
multiply everything by 6...to get rid of the fractions
6x+2-3=18x-3
now...combine like terms on each side
6x-1=18x-3
2=12x
x=2/12=1/6
2007-11-30 12:16:19 · answer #5 · answered by jbe 2 · 0⤊ 0⤋
you have, x+1/3-1/2=3x-3/6 (multiply throughout by 2)
x+1/3-1=3x-3/3
x+1/2=3x-3/3 (multiply throughout by 6)
3(x+1)=2(3x-3)
3x+3=6x-6 (subtract 3x+3 on both sides)
3x-9=0 (divide throughout by 3)
x-3=0 thus x=3
2007-11-30 12:19:19 · answer #6 · answered by silent R 1 · 0⤊ 0⤋
x+1/3-1/2=3x-3/6
multiply throught with 6
6x+2-3=18x-3
6x-1=18x-3
-1+3=18x-6x
2=12x
2/12=x
1/6=x
2007-11-30 12:08:45 · answer #7 · answered by Siva 5 · 0⤊ 0⤋
l.c. m is 6
6x+2-3=18x-3
2= 12x
x=2/12=1/6
2007-11-30 12:06:38 · answer #8 · answered by Little Princess 1 · 0⤊ 0⤋
it is wrong
x=1/6
2007-11-30 12:08:58 · answer #9 · answered by osman c 1 · 0⤊ 0⤋
you did it right
2007-11-30 12:04:36 · answer #10 · answered by Chiquita 4 · 0⤊ 0⤋