CD is a diameter of the circle ...?

Question

CD is a diameter of the circle with center at A and CDHG is a square. What is the area of the irregular polygon CGHD in terms of r?

Answer 1

Irregular polygon? I though you said CGHD was a square (changing the lettering in this case makes no difference).

Radius = r
Diameter = CD = 2r

Since CGHD is a square,

ar (CGHD) = 4r^2

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Will P, a circle or a semicircle does not count as a polygon. A polygon is a simple closed figure composed of only line segments. A semicircle has a curve.

Answer 2

it would be [(pi*r^2)/2] (the area of half the circle) + (2r)^2 (the area of the square).

answersgeek: i believe the question was asking for the area of a polygon that is a square superimposed on a circle, so basically a half circle connected to one side of a square, where the diameter of the circle is also the connecting side of the square. that figure (the polygon) has an area of half the circle plus the square.