solve math problem please?

Question

2/x-1=3/x

Answer 1

The first important rule is that x≠0 or 1!

Multiply both sides by x(x-1):
2x=3(x-1)
2x=3x-3
-x=-3
x=3

Check:
2/(3-1)=3/3
2/2=3/3
1=1

Answer 2

(x - 1) can be totally in the denominator or the denominator on the LHS may only have x. I'll solve both.

2/(x - 1) = 3/x
-> 2x = 3x - 3
-> x = 3

(or)

(2/x) - 1 = 3/x
-> 2 - x = 3 (Multiplying by x on both sides)
-> x = -1

Answer 3

I suppose you want to write 2/(x-1) = 3/x The parenthesis are important here.

Just multiply in cross: (but remembering that x cannot be zero or 1)

2x = 3(x-1) ==> 2x = 3x - 3 ==> 3x - 2x = 3 ==> x = 3 OK

Answer 4

2x + 2y = 20 using the simultaneous technique 2x - 2y = 4 ____________ 4x = 24 ( divide by using 4) x = 6 exchange x in considered one of the two equations 2x + 2y = 20 2 (6) + 2y = 20 12 +2y = 20 2y = 20 - 12 2y = 8 (divide by using 2) y = 4 answer : X = 6 , Y = 4

Answer 5

x=-1

Answer 6

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Answer 7

2/x-1=3/x
2/(-1)-1 =3/(-1)
-2-1 = -3
-3=-3
X=-1

Answer 8

2/x-1=3/x
l.c.m= x
2-x=3
-x=1
x=-1

Answer 9

2/x-1=3/x
multiply throught out with x
2-x=3
-x=3-2
-x=1
x=-1

Answer 10

multiply both sides by x to begin with
x(2/x-1)=3/x(x)
you get:
2-x=3
then solve for x, and you get x=-1