if 28.2 g C20 H42 is dissolved in 500 g of C6H6(pure P 25 degrees = 93.4 torr), then what is the vapor pressure (in Torr) of the solution at 25.0 degrees celcius.
2007-11-30 02:56:55 · 2 answers · asked by confusedkid 3 in Science & Mathematics ➔ Chemistry
Vapour pressure of benzene in the solution = vapour pressure of benzene x mole fraction of benzene
moles solute = g solute/(formula weight of solute)
Moles benzene = g benzene/(formula weight of benzene)
Mole fraction benzene = (moles benzene)/(total moles of everything)
2007-11-30 03:03:07 · answer #1 · answered by Facts Matter 7 · 0⤊ 0⤋
first we discover moles: 3.2 g / 102.6g/mol = .0311 mol next we prefer the molarity of the answer molality is moles of solute according to Kg of solvent 50g = .05Kg .0311 / .05 = .622 now we multiply by utilising the Kf (a million.86°C / molal) .622 x a million.86 = a million.1569 or a million.sixteen rounded so your answer is: -a million.sixteen°C
2016-11-13 01:42:46 · answer #2 · answered by weichman 3 · 0⤊ 0⤋