Can someone give me proof that XeF4 is a violation of the octet rule for Xe, a noble gas?

Question

I know noble gases are the most inclined to follow the octet rule, but I'm fairly certain Xe doesnt -- because there is an extended octet. Is an extended octet a direct violation of the octet rule, and does Xe violate it in this way despite its nobility? Thank you so much in advance.

Answer 1

Well, usually noble gases do not react. Elements react in order to form a stable structure, but, since noble gases already have one, they don't have to react.
Under special conditions of high pressure and very low temperature, they react. That's how compounds of noble gases formed.
There are also KrF4, XeO3, XeO4, XeF8, H6XeO6, KrF2, H2KrO4.
Have a nice day! Louise

Answer 2

Noble gases are noble because their outer electron configuration is stable, Including a complete octet.

However, as soon as they start sharing electrons contributed by other atoms, the that forces them to expand the octet.

Expansion of the octet in noble gases, as in the example you quote, or in other compounds (SiF6, for example), it is indeed a direct violation (a gentler term is "breakdown") of the octet rule.

Answer 3

Xe in its elementary form has an octett that makes it a noble gas, in XeF4 it shares these octett pairs with one F each - > violation !