A box slides down a 27° ramp with an acceleration of 1.06 m/s2. Determine the coefficient of kinetic friction

Answer 1

The net force is equal to mass time acceleration
looking at a FBD of the box, and summing the forces parallel to the surface of the ramp, we have

Gravity
m*g*sin(27)
and friction
-m*g*cos(27)*µk

setting up the equation F=m*a
m*g*(sin(27)-cos(27)*µk)=m*1.06
solve for µk
µk=0.388

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