4- l x-4 l Closed Interval [1,6]
Find the min and max
2007-11-28 19:37:34 · 4 answers · asked by Adam d 1 in Science & Mathematics ➔ Mathematics
if x>=4
f(x)=4-x+4=8-x
f(4)=4
f(5)=3
f(6)=2
if x<4
f(x)=4+x-4=x
f(1)=1
f(2)=2
f(3)=3
min value =1
max value=4
2007-11-28 19:47:12 · answer #1 · answered by iyiogrenci 6 · 0⤊ 0⤋
The function can be decomposed as
4 - ( 4- x) = x x<4
4 - (x - 4) = 8 -x x >4
the 1st function is increasing, the 2n decreasing
therefore we have max. at x = 4 with value of 4
we then have to compare values at boundaries
x(1) = 1
x(6) = 2
therefore min is 1
2007-11-29 03:49:15 · answer #2 · answered by Maurizio S 2 · 0⤊ 0⤋
4-|x-4|=4-x-4=x for x>4 Therefore max=6
4-|x-4\=4-4-x=-x for x<4 Therefore min=-1
2007-11-29 03:44:12 · answer #3 · answered by ramesh_1960 3 · 0⤊ 0⤋
for x>4
4-|x-4| = 4-(x-4) = 8-x max 4
for x - 4, 4
for x<4
4-|x-4| = 4-(4-x) = x min 1
2007-11-29 03:48:29 · answer #4 · answered by holdm 7 · 0⤊ 0⤋