Can anyone help me solve this problem? I am new at this and I am a little confused.
2007-11-28 19:01:41 · 8 answers · asked by Syl 2 in Science & Mathematics ➔ Mathematics
You solve much like an equality.
8x + 10 > 7x + 11
Subtract 7x from both sides:
x + 10 > 11
Subtract 10 from both sides:
x > 1
P.S. The only difference between this and equalities is if you multiply or divide by a negative number. Then you need to switch the direction of the sign. But here we only used subtraction.
2007-11-28 19:07:11 · answer #1 · answered by Puzzling 7 · 2⤊ 3⤋
x>1
2007-11-29 03:20:12 · answer #2 · answered by drmobaid 2 · 0⤊ 0⤋
x > 1
2007-11-29 07:50:12 · answer #3 · answered by Jeff M 2 · 0⤊ 1⤋
8x + 10 > 7x + 11, trnsposing to other sides
=> 8x -- 7x > 11 -- 10
=> x > 1
2007-11-29 04:03:13 · answer #4 · answered by sv 7 · 0⤊ 1⤋
solve it as normal eg 8x +10 > 7x +11
colect all x terms and number which gives u x >1 like take 7x to the other side and 10 to the left hand side no problem
2007-11-29 03:08:15 · answer #5 · answered by Anonymous · 1⤊ 1⤋
Get x alone on one side
8x + 10 > 7x + 11
x+10>11 (subtract 7x from both sides)
x>1 (subtract 10 from both sides)
Remember if you do something to one side oyu MUST do the same to the other!!
2007-11-29 03:07:21 · answer #6 · answered by Anonymous · 1⤊ 1⤋
x > 11 - 10
x > 1
2007-11-29 03:48:36 · answer #7 · answered by Como 7 · 1⤊ 1⤋
8x+10>7x+11
Subtracting 7x from both sides,we get
x+10>11
Subtracting 10 from both sides,we get
x>1
This is the answer.Hope you understand.
2007-11-29 03:38:28 · answer #8 · answered by Anonymous · 0⤊ 0⤋