Math Stumper?

Question

x^3+x^2+2x+6...

I am tired and yet I am still lost with this problem... I have tried to work it 3 different ways and still can not figure it out??? can someone help me please ......

You are supposed to factor it completely...... sorry I thought I put that in there....

Answer 1

Are you sure you copied it down correctly? I've also tried factoring it into integer roots and it doesn't come out correctly.

Because you have all + signs, that tells me there are no positive roots. If you switch the signs on the odd powers that tells me there are either 3 or 1 negative roots.

Negative roots would come from the set {-1, -2, -3, -6} but none of these come out evenly as zeroes of the function.

If I run it through a polynomial solver, it comes out with the following roots:
X1 = 0.38802 - 1.7966i
X2 = 0.38802 - 1.7966i
X3 = -1.77605

That's one real root and two imaginary roots. This is definitely not going to factor nicely into integer roots.

Can you double-check your question?

One way that this could come out evenly would be if the last coefficient was 2, instead of 6.

x^3 + x^2 + 2x + 2

Factor an x² out of the first two terms:
x²(x + 1) + 2x + 2

Now factor a 2 out of the last two terms:
x²(x + 1) + 2(x + 1)

Now factor out the common x + 1:
(x² + 2)(x + 1)

Could this have been your actual question?

Answer 2

Maybe if you wrote out the entire problem, we could help you.

All I see is "x^3+x^2+2x+6...".

Is there an equal sign somewhere in there?

Answer 3

what are u supposed to do? factor it? be more specific with your question

Answer 4

Well if that's all you have to work with, your question is the answer....

Answer 5

what are you trying to do? solve for x? integrate? differentiate?