2007-11-28 16:33:08 · 4 answers · asked by EP 2 in Science & Mathematics ➔ Mathematics
(5+8x)(7+5x+4x^2)^(-1\2)
let u= 7+5x+4x^2
du= 5+8x dx
u^(1\2)/(1\2) = 2u^(1\2) + C
2(sqrt(7+5x+4x^2) +C
2007-11-28 16:42:25 · answer #1 · answered by chperez2004 2 · 0⤊ 0⤋
you will want to use the substitution rule to solve this integral.
let u=7+5x+4x^2
and du = 5+8x dx
this leaves you with the integral of 1/sqrt (u)
or you could simplify by evaluating the integral of u^(-1/2)
once integrated you get 2u^1/2.
just substitute the u back in and you have your solution.
2007-11-29 00:45:51 · answer #2 · answered by Rox 2 · 0⤊ 0⤋
Use the substitution u = 7 + 5x + 4x²; then du = (5 + 8x) dx
2007-11-29 00:41:56 · answer #3 · answered by Ron W 7 · 0⤊ 0⤋
http://integrals.wolfram.com/index.jsp
2007-11-29 01:02:56 · answer #4 · answered by boyaydmband 2 · 0⤊ 0⤋