An airplane is flying horizontally with speed 800 km/h (222 m/s) when an engine falls off. Neglect air resistance, and assume it takes 20 s for the engine to hit the ground.
How high is the airplane? in meters
How far horizontally does the engine travel while it falls? in meters
2007-11-28 15:57:45 · 1 answers · asked by joe s 1 in Science & Mathematics ➔ Physics
This is a two-dimensional kinematics problem. We'll start with the vertical dimension. The equation of motion we'll use is
y - yo = voy t - 1/2 g t^2
where y - yo is the distance fallen, voy is the initial vertical velocity (zero), g is the local acceleration of gravity (9.8 m/s^2), and t the elapsed time (20 sec). Plug in the values to find the distance fallen.
In the horizontal dimension, the equation of motion is
x - xo = vox t
where x - xo is the distance traveled, vox is the initial velocity in the x dimension (222 m/s), and t is the time (20 s). Plug in those values to find the horizontal distance traversed.
2007-11-28 16:03:21 · answer #1 · answered by jgoulden 7 · 0⤊ 0⤋