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2007-11-28 15:41:07 · 9 answers · asked by CARLOS L 2 in Science & Mathematics Mathematics

9 answers

A = (1/2) b h
2A = b h
b = 2 A / h

2007-11-28 19:13:57 · answer #1 · answered by Como 7 · 2 2

A=1/2bh [b]
2A=bh (multiply both sides by 2 to get rid of 1/2)
(2A)/h=b (divide both sides by h)

Then just put in your numerical values of A and h and you will get b. A will be the area of triangle you are working with, h will be its height and b is its base.

2007-11-29 16:24:51 · answer #2 · answered by Perfect-Angel84 2 · 0 1

A = 1/2bh cross multiply :: 2bhA = 1 :: b = 1/2hA

2007-11-29 07:01:59 · answer #3 · answered by Paddy 4 · 0 1

A = 1/2bh (multiplied both sides by 2)

2A = bh (divided both sides by h)

b = (2A)/h

2007-11-28 23:47:20 · answer #4 · answered by frank 7 · 1 1

It looks like you're working with triangles. The area of a triangle is

A = 1/2 (B)(H)

where A is the area, B the base, and H the height (many books say "altitude" here).

Rearranging to isolate B yields

B = 2 A / H

2007-11-28 23:46:36 · answer #5 · answered by jgoulden 7 · 2 2

1. A = 1/2bh
2. Ax2= bh (that's A times 2)
3. (Ax2)/h (A times 2 all divided by h)
4. b= (2A)/h

hope it helps

2007-11-28 23:46:30 · answer #6 · answered by marmaladeskies 7 · 1 0

Assuming you're given the figures for A and h, rearrange the equation to b = 2A/h, then solve for b.

2007-11-28 23:45:47 · answer #7 · answered by RavenSierra 3 · 1 0

Multiply both sides of the equation by 2 and divide both by h.

2007-11-28 23:48:09 · answer #8 · answered by Tim C 7 · 0 2

simple just add π2x γ2

2007-11-28 23:44:55 · answer #9 · answered by Nick K 2 · 1 0

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