A = (1/2) b h
2A = b h
b = 2 A / h
2007-11-28 19:13:57
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answer #1
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answered by Como 7
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A=1/2bh [b]
2A=bh (multiply both sides by 2 to get rid of 1/2)
(2A)/h=b (divide both sides by h)
Then just put in your numerical values of A and h and you will get b. A will be the area of triangle you are working with, h will be its height and b is its base.
2007-11-29 16:24:51
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answer #2
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answered by Perfect-Angel84 2
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A = 1/2bh cross multiply :: 2bhA = 1 :: b = 1/2hA
2007-11-29 07:01:59
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answer #3
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answered by Paddy 4
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A = 1/2bh (multiplied both sides by 2)
2A = bh (divided both sides by h)
b = (2A)/h
2007-11-28 23:47:20
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answer #4
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answered by frank 7
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It looks like you're working with triangles. The area of a triangle is
A = 1/2 (B)(H)
where A is the area, B the base, and H the height (many books say "altitude" here).
Rearranging to isolate B yields
B = 2 A / H
2007-11-28 23:46:36
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answer #5
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answered by jgoulden 7
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1. A = 1/2bh
2. Ax2= bh (that's A times 2)
3. (Ax2)/h (A times 2 all divided by h)
4. b= (2A)/h
hope it helps
2007-11-28 23:46:30
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answer #6
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answered by marmaladeskies 7
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Assuming you're given the figures for A and h, rearrange the equation to b = 2A/h, then solve for b.
2007-11-28 23:45:47
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answer #7
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answered by RavenSierra 3
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Multiply both sides of the equation by 2 and divide both by h.
2007-11-28 23:48:09
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answer #8
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answered by Tim C 7
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simple just add Ï2x γ2
2007-11-28 23:44:55
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answer #9
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answered by Nick K 2
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